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The voltage across a wire is (100+-5)v a...

The voltage across a wire is `(100+-5)v` and the current passing through it is `(10+-0.2)A`.

Text Solution

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Voltage `V= (100pm 5)V`
Current `I=(10pm0.2)A`
Resistance `R=`?
Then resistance R is given by Ohm's law
`R=(V)/(I)=(100)/(10)=10Omega`
`(DeltaR)/(R)=((DeltaV)/(V)+(DeltaI)/(I))`
`DeltaR=((DeltaV)/(V)+(DeltaI)/(I))R=((5)/(100)+(0.2)/(10))xx10`
`=(0.05+0.02)xx10=0.07xx10=0.7`
The resistance `R=(10pm0.7)Omega`
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