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If the distance D between an object a...

If the distance D between an object and screen than 4 times the focal length of a convex lens, then there are two positions of the lens for which image are formed on the screen. This method is called conjugate method. If d is the distance between the two positions of the lens, obtain the equation for focal length of the convex lens.

Text Solution

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Mirror `1/f = 1/v + 1/u`
Lens us eliminate v by substituting v = D- u
` (1)/(D - u) + 1/u - 1/f`
We get the equation `u^2 - Du + fD = 0`
Quaratic equation ` u = ( D pm sqrt(D^2 - 4fD))/(2)`
` mu_1 = (D - sqrt(D^2 - 4fD))/(2)`
`v_1 = D - u_1 = (D + sqrt(D^2 - 4fD))/(2)`
after changing
`mu_1 = (D + sqrt(D^2 - 4f D))/(2)`
` v_2 = D - u_2 = (D - sqrt(D^2 - 4fD))/(2)`
now the displacement
` d = v_1 - u_1 - u_2 - v_2 = sqrt(D^2 - 4fD)`
` f = (D^2 - d^2)/(4D)`
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If the distance D between an object and screen is greater than 4 times the focal length of a convex lens, then there are two positions of the lens for which images are formed on the screen. This method is called conjugate foci method. If d is the distance between the two positions of the lens, obtain the equation for focal length of the convex lens.

The focal length of i1 convex lens is positive.

Knowledge Check

  • If the focal length of a convex lens is 1 m then its power is :

    A
    1 dioptre
    B
    0.1 dioptre
    C
    10 dioptre
    D
    0.01 dioptre
  • The focal length of a lens is the distance between:

    A
    optic centre and principal focus
    B
    optic centre and centre of curvature
    C
    principal focus and centre of curvature
    D
    none
  • The sign of focal length of a convex lens is …….. Sign.

    A
    negative
    B
    positive
    C
    negative or positive
    D
    none of the above
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