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The critical angle for a given piece of ...

The critical angle for a given piece of glass is `45^@` . Calculate the polarising angle for it. Also calculate the angle of refraction when light is incident on this glass at an angle of incident equal to `i_P`

Text Solution

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Formula : We know `sin i_c = 1/mu`
`mu = (1)/(sin i_c) = (1)/(sin 45^@) = sqrt2`
According to Brewster's law
` tan i_P = mu = sqrt2`
`rArr i_P = tan^(-1) sqrt(2) = tan^(-1) (1.414) = 51^@41'`
When light is incident at an angle `i_P` the corresponding angle of refraction 'r' is given by
` i_P + r = 90^@ `
` therefore r = 90^@ - (51^@ 40') = (38^@ 20')`
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