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For a glass (mu= sqrt(3) ) the angle of ...

For a glass `(mu= sqrt(3) )` the angle of minimum deviation is equal to the angle of the prism. Find the angle of the prism.

Text Solution

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At minimum deviation `mu = (sin ((A+ delta_m)/(2)))/(sin (A/2))`
Given ` delta_m = A`
`mu = (sin A)/(sin A/2) = (2 sin A/2 cos A/2)/(sin A/2)`
` = 2 cos A/2`
` therefore cos A/2 = (sqrt3)/(2) " or " A/2 = 30 " " A = 60^@`
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