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A ray of light incident on an equilatera...

A ray of light incident on an equilateral glass prism shows minimum deviation of `30^(@)`. Calculate the speed of light through the prism.

Text Solution

Verified by Experts

Given : (i) Here A = `60^@ , delta_m = 30^@`
We know that
Formula: ` mu = (sin ((A +delta_m)/(2))/(sin (A/2))`
` = (sin ((60^@ + 30^@)/(2)))/(sin ((60^@)/(2))`
` (sin 45^@)/(sin 30^@) = sqrt2`
Also `mu = c/v rArr v = (3 xx 10^8)/(sqrt2) m//s`
` = 2.122 xx 10^8 m//s`
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