In young's double slit experiment, the angular width of a fringe is found to be `0.2^@` on a screen placed 1 m away. The wavelength of light used is 600 nm. What will be the angular width of the fringe if the entire experimental apparatus is immersed in water? Take refractive index of water as `4/3` .

Explanation

Formula :Angular fringe width =` beta/D = lamda/d`
If apparatus is dipped in water, `lamda` changes to
` lamda_w = (lamda)/(n_w) = (lamda)/(4/3) = (3 lamda)/(4)`
` therefore ` New angular fringe width
` theta_w = (lamda_w)/(d)`
`therefore (theta_w)/(theta) = (lamda_w)/(lamda) = ((3lamda)/(4))/(lamda) = 3/4`
` theta_w = 3/4 theta = 3/4 xx 0.2^@ = 0.15^@`