Home
Class 12
PHYSICS
Light falls from glass (mu = 1.5) to air...

Light falls from glass (`mu` = 1.5) to air. Find the angle of incidence for which the angle of deviation is `90^@` .

Text Solution

Verified by Experts

`sin i_c = (1)/(mu) = (1)/(1.5) = 0.6667 `
or `i_c = 41.8^@`
Deviation `=90^@ - i_c = 90^@ - 41.8^@ = 48.2^@`
This is the maximum attainable deviation in refraction. So, the given data favours total internal reflection.
In reflection, deviation ` = 180^@ - 2i`
or `90^@ = 180^@ - 2i " or " 2i = 90^@`
` i = 45^@`
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the angle of incidence called, when angle of refraction is 90^(@) ?

TRUE or FALSE: If angle of incidence is zero, then the angle of refraction is 90^(@) .

Light is incident from glass (mu = 1.50) to water (mu = 1.33) find the range of the angle of deviation for which there are two angles of incidence.

The angle of incidence for a ray of light having zero reflection angle is

Light rays travel from vacuum into glass whose refractive index is 1.5 If the angle of incidence is 30^(@) calculate the angle of refraction inside the glass.

A light travels from air into water, the angle of refraction is 25^@ to the normal. Find the angle of incidence. Refractive index of water is 1.33 . mu_a =1

A ray light fall on a plane surface at an angle of incidence 9^@ and reflection occurs. Calculate the angle of reflection in degree.

An equilateral glass prism has a refractive index of 1.5 Calculate the (a) angle of incidence for minimum deviation, (b) the minimum deviation, (c) the angle of emergence of the light at the maximum deviation .