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The de Broglie wavelength associated wit...

The de Broglie wavelength associated with an electron accelerated through a potential differenece V is `lambda`. What will be its wavelength when the accelerating potential is increased to 4V ?

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`lambda = ( h )/( sqrt( 2m qV)), lambda' = ( h )/( sqrt( 2m e( 4V)))= ( lambda)/( 2)`
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