A proton and an electron have same velocity. Which one has greater de Broglie wavelength and why ?

Explanation

de Broglie wavelength ( `lambda` ) is given is `lambda = ( h )/( m ) `
Given `v_(p) = v_(e ) `
where ` v_(p)` = velocity of proton and
`v_(e ) = ` velocity of electron
since `m_(p) gt m_(e ) `
From the given relation
`lambda prop ( 1)/( m ) ` , hence `lambda _ ( p ) lt lambda _( e ) `