An electron and a proton, each has a wavelenght of 1.00 nm. Find
the energy of the photon

Explanation

Energy of photon
`E= h upsilon= h xx ( c)/( lambda ) = ( h )/ ( lambda) xx c = pc `
`= pc = 6.63 xx 10^(-25) xx 3 xx 10^(8) J`
` = 19.89 xx 10^(-17) J`
`= ( 19.89 xx 10^(-17))/( 1.6 xx 10^(-19)) eV = 1.24 xx 10^(3) eV`
`= 1.24 keV`