An electron and a proton are moving in the same direction and possess same kinetic energies. Find the ratio of de Broglie wavelength associated with these particles.

Explanation

`K.E. =( 1)/( 2) mv^(2) = ( p^(2))/( 2m ) ` or `p= sqrt( 2 m ( K.E))`
de Broglie wavelength `, lambda = ( h )/( p )`
`:. ( lambda _("electron"))/( lambda_("proton")) = ( p_("proton"))/( p_("electron")) = sqrt((2m_(p)(K.E.))/(2m_(e ) (K.E.)))`
`= sqrt((m_(p))/( m_(e )))`