Home
Class 12
PHYSICS
For photoelectric effect in sodium, the ...

For photoelectric effect in sodium, the figure shows the plot of cut-off voltage versus frequency of incident radiation. Calculate
work function for sodium

Text Solution

Verified by Experts

Work function `W =hv_(0)`
`= 6.6 xx 10^(-34 ) xx 4.5 xx 10^(14) `joule
`= ( 6.6 xx 10^(-34) xx 4.5 xx 10^(14))/(1.6 xx 10^(-19)) eV = 1.85 eV`
Promotional Banner

Similar Questions

Explore conceptually related problems

In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12xx10^(-15)V s. Calculate the value of Planck's constant.

According to Einstein's photoelectric equation, the plot of the K.E. of the emitted photoelectrons from ametal vs the frequency of incident radiation gives a straight line where slope

In photoelectric effect, a graph is drawn taking the frequency of incident radiation along X-axis and the corresponding stopping potential along the Y-axis. The nature of the graph is :

The above graph shows frequency of an incident photon and maximum kinetic energy of a photoelectric effect a. What is the value of threshold frequency and threshold wave-length? b. What is the work function of the cathode in eV? c. Find the maximum kinetic energy, if the frequency of photon is 9xx10^(14) Hz. d. Also find the value of Planck's constant (h).

For photoelectric emission from certain metal the cut -off frequency is v . If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be(m is the electron mass).

The photoelectric work function for a metal surface is 4.125 eV. The cut off wavelength for this surface is

a. Every metal has a definite work function. Why all photoelectrons do not come out with the same energy of incident radiation in monochromatie ? Why there is an energy distribution of photoelectrons? b. The energy and momentum of an electron are related to the frequency and wave-length of the associated matter wave by the relations, E=h upsilon, p=(h)/(lambda) But while the value of lambda is physically significant, the value of upsilon (and therefore the value of the phase speed upsilon lambda has no physical significance. Why?