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An electron and a proton, each have de B...

An electron and a proton, each have de Broglie wavelength of 1.00 nm.
Find the ratio of their momenta.

Text Solution

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`lambda_(e ) = ( h )/( p_(e )) ` and `lambda_(p)= ( h )/( p_(p)) , lambda_(e ) = lambda_(p) = 1.00nm`
So, `( lambda_(e))/(lambda_(p)) = ( p_(p))/( p_(e)) = ( 1)/( 1) rArr (p_(p))/( p_(e)) = ( 1)/( 1) = 1:1``
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