The given circuit has two ideal diodes connected as shown in figure below. Calculate the current flowing through the resistance `R_(1)`

Explanation

Given Date :
Applied voltage `V=10V`
`R_(1) = 2 Omega: R_(2) = 3 Omega:R_(3) = 2 Omega:`
Effective resistance `=R_(1)+R_(2)`
`=2+2=4Omega`
`D_(1)` is reverse biased . So no current flows in the branch of diode `D_(1)` . (Block the current )
`D_(2)` is forward biased and effects no resistance in the circuit . (pass the current )
`:.` Current `I=(V)/(R)=10/4`
`I=2.5A`