In the given figure, the value of x is

Explanation

Given date :
`V_("CEsat")=0.2V`
`beta=50`
` V_("CC") =3V`
`R_(C)=1kOmega("or")10^(3)Omega`
`I_(C)` = collector current
`I_(B)` = base current
To find :
`I_(B)=?`
`V_(CE)=V_("CC")-I_(C)R_(C)`
`Ic_("sat")=(V_("CC")-V_("CEsat"))/(R_(C))`
`:. Rc = 1 k `
`Ic_("sat")=(3-0.2)/(1Omega)=2.8mA`
`I_("B min")=(I_(C))/(beta)`
`=(2.8mA)/(50)=56muA`
`I_(B)=56muA`