Home
Class 12
PHYSICS
In the circuit shown in the figure, the ...

In the circuit shown in the figure, the BJT has a current gain `(beta)` of 50. For an emitter - base voltage `V_(EB)= 600 mV`. calculate the emitter - collector voltage `V_(BC)` (in volts).

Text Solution

Verified by Experts

Give date :
Current gain `(beta)=50`
Emitter base voltage `V_(EB)=600mV=600xx10^(-3)V`
`R_(B)=60KOmega=60xx10^(3)Omega`

`R_(E)=500KOmega=500xx10^(3)Omega`
`V_("EB")-V_(E)-V_("EB")`
`V_(B)=3-0.6=2.4V`
`I_(B)=(V_(B))/(60K)=(2.4)/(60K)=40muA`
`I_(C)=beta.I_(B)=50xx40muA=2mA`
`V_(C)=R_(E).I_(C)=500I_(C)`
`=500xx2mA=1V`
`V_(C)=1V`
So, `V_(EC)=V_(E)-V_(C)=3-1=2V`
`V_(EC)=2V`
Promotional Banner

Similar Questions

Explore conceptually related problems

The plate current in a diode is 20 mA when the plate voltage is 50 V or 60 V . What will be the current if the plate voltage is 70 V ?

In the circuit shown in the figure, the input voltage V_i = +5 V, V_(BE) = + 0.8 V and V_(CE) = +0.12 V . Find the values of I_B I_C and beta .

In the circuit shown in the figure , the input voltage V_i is 20 V, V_BE =0V and V_CE =0V. What are the value of I_B,I_C,beta ?

Calculate the emitter current in a transistor for which beta = 50 , base current I_(B) = 25 mu A .

For a BJT circuit shown , assume that the 'beta' of the transistor is very large and V_(BE)=0.7V. The mode of operation.

An AC source is rated 220 V, 50 Hz . The average voltage is calculated in a time interval of 0.01 s . It