If `sin(theta/2)=a, cos(theta/2)=b` then `(1+sin theta)/(3sin theta+4cos theta+5)=`

4 sin 5 theta cos 3 theta sin 2 theta

3. sin^(3)theta+cos^(3)theta=(sin theta+cos theta)(1-sin theta cos theta)

If 3sin theta =2 cos theta , then (4sin theta - cos theta)/(4cos theta+sin theta) is equal to :

If 3 sin theta=2 cos theta , then 3 sin theta=2 cos theta , then (4 sin theta-cos theta)/(4 cos theta+sin theta) is equal to: यदि 3 sin theta=2 cos theta है, तो 3 sin theta=2 cos theta , then (4 sin theta-cos theta)/(4 cos theta+sin theta) का मान क्या होगा ?

Prove that: (sin^(3) theta + cos^(3) theta)/(sin theta + cos theta) = 1-sin theta cos theta

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

2 cos (theta - pi //2) + 3 sin (theta + pi//2) - (3sin theta + 2 cos theta ) = ? A. cos theta - sin theta B. sin theta - cos theta C. sin theta + cos theta D. cot theta - tan theta .

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta