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If cos theta=(a cosphi+b)/(a+bcosphi) th...

If `cos theta=(a cosphi+b)/(a+bcosphi)` then `tan(theta/2)/tan(phi/2)=` (A) `(a-b)/(a+b)` (B) `(a+b)/(a-b)` (C) `sqrt((a+b)/(a-b))` (D) `sqrt((a-b)/(a+b))`

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