If `tan (alpha/2)` and `tan beta/2`are the roots of the equation `8x^2-26x+15=0`then the `cos(alpha+beta)` is equal to

If tan(alpha/2) and tan(beta/2) are the roots of the equation 8x^2-26x+15=0 then cos(alpha+beta) is equal to

If tan((alpha)/(2)) and tan (( beta)/(2)) are the roots of the equation 8x^(2)-26x+15=0 then cos (alpha+ beta)=

If tan""(alpha)/(2)andtan""(beta)/(2) are roots of the equation 8x^(2)-26x+15=0 then cos(alpha+beta) = …………

If tan "" (alpha )/(2) and tan "" (beta)/( 2) are the roots of the equation 8x ^(2) -26x + 15 =0, then find the value of cos (alpha + beta).

If tan "" (alpha )/(2) and tan "" (beta)/( 2) are the roots of the equation 8x ^(2) -26x + 15 =0, then find the value of cos (alpha + beta).

If tan alpha and tan beta are the roots of the equation x^(2) +px + q = 0 , then the value of sin^(2) (alpha +beta) + p cos (alpha + beta) sin (alpha + beta) + q cos^(2) (alpha + beta) is

Given that tan alpha and tan beta are the roots of the equation x^(2)+bx+c=0 with bne0 . What is tan(alpha+beta) equal to ?

If "tan"(alpha)/(2) and "tan"(beta)/(2) are the roots of the equation 8x^(2)-26x+15=0 , then find the value of "tan"((alpha+beta)/(2))