" 10) "(x)/(x+1)+(x+1)/(x)=(34)/(15)

Solve the following quadratic equations by foctorization methd: (x)/(x+1)+(x+1)/(x)=(34)/(15),x!=0,x!=-1

Algorithm to Solve the equation by factorization method (x)/(x+1)+(x+1)/(x)=(34)/(15)

(x)/(x+1)+(x+1)/(x)=(34)/(15),(x!=0,-1)

Solve for x , x/(x + 1) + (x + 1)/x = 34/15

Solve the following quadratic equations by factorization method: x/(x+1)+(x+1)/x=(34)/(15),x!=0,x!=-1

(x-1)(x-2)(x-3)(x-4)=15

The series expansion of log_(e) [(1 + x^((1 + x))(1-x)^(1-x)] is (1) 2[(x^(2))/(1.2) + (x^(4))/(3.4)+(x^(6))/(5.6)+...] (2) [(x^(2))/(1.2) + (x^(4))/(3.4)+(x^(6))/(5.6)+...] (3) 2[(x^(2))/(1.2) + (x^(4))/(2.3)+(x^(6))/(3.4)+...] (4) 2[(x^(2))/(1.2) -(x^(4))/(2.3)+(x^(6))/(3.4)-...]

Solve: x+(1)/(x)=25(1)/(25)(x-3)(x-4)=(34)/((33)^(2))

Solve the following quadratic equation by the method of factorisation:(xxii) x/(x+1)+(x+1)/x=34/15,x!=0,x!=-1

If A = [[x, -2],[3, 7]] and A^(-1) = [[(7)/(34), (1)/(17)],[(-3)/(34), (2)/(17)]] , then the value of x is