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(2)/(3)+(3)/(4)+(1)/(2)...

(2)/(3)+(3)/(4)+(1)/(2)

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2(3)/(4)+3(1)/(2)

3(2)/(3)+2(3)/(4)+1(1)/(2)=?

5(1)/(2)-[2(1)/(3)-:[(3)/(4)-(1)/(2)times((2)/(3)-(1)/(24))]]

It is given that the events A and B are such that P(A)=(1)/(4),P((A)/(B))=(1)/(2) and p((B)/(A))=(2)/(3) Then P(B) is: (1)(1)/(6)(2)(1)/(3)(3)(2)/(3)(4)(1)/(2)

1 (2)/(3) + 2 (1)/(3) + 2 (2)/(3) - 4 (1)/(2) =

((1)/(2) . (2)/(2))/(1^(3))+((2)/(3) . (3)/(2))/(1^(3)+2^(3)) +((3)/(2) . (4)/(2))/(1^(3)+2^(3)+3^(3))+.. . . to n terms

((1)/(2), (2)/(2) )/(1^3) + ((2)/(2) , (3)/(2) )/( 1^3 + 2^3) + ((3)/(2) , (4)/(2) ) / (1^(3) + 2^(3) + 3^(3) ) + ..... n terms

Find sum: (1)/(2) + (1)/(3^(2)) + (1)/(2^(3)) + (1)/(3^(4)) + (1)/(2^(5)) + (1)/(3^(6))+ …..oo

[(-2(3)/(4))-(-1(3)/(4))]+[(-2(3)/(4))-(-1(3)/(4))]+ upto 30 terms is