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=0" 31) "9x=2y+7quad " (iv) "(x)/(2)+(2y...

=0" 31) "9x=2y+7quad " (iv) "(x)/(2)+(2y)/(3)=-1" 3th "x-(y)/(3)=3

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Solve the following pair of linear equations by the elimination method and the substitution method: (i) x+y=5" "a n d" "2x 3y=4 (ii) 2x+4y=10" "a n d" "2x 2y=2 (iii) 3x 5y 4=0" "a n d" "9x=2y+7 (iv) x/2+(2y)/3=-1 and x-y/3=3

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

If 7x - 15y = 4x + y , find the value of x: y . Hence, use componendo and dividendo to find the values of : (i) (9x + 5y)/(9x - 5y) (iI) (3x^(2) + 2y^(2))/(3x^(2) - 2y^(2))

On comparing the ratios (a_(1))/(a_(2)),(b_(1))/(b_(2)) and (c_(1))/(c_(2)), find out whether the following pair of linear equations are consistent,or inconsistent.(i) 3x+2y=5;2x-3y=7( ii) 2x-3y=8;4x-y=9 (iii) (3)/(2)x+(5)/(3)y=7;9x-10y=14( (iv) 5x-3y=11;-10x+6y=-22( v) (4)/(3)x+2y=8;2x+3y=12

Simplify: (3x+2y)(4x+3y)-\ (2x-y)(7x-3y)