y=e^(x)+1quad =y''-y'=0

Verify that the given functions ( explicit or implicit ) is a solution of the corresponding differential equation : y=e^(x)+1:y''-y'=0

Verify that the given functions (explicit or implicit is a solution of the corresponding differential equation: y=e^(x)+1:y''-y'=0

Verify that the given functions(explicit or implicit) is a solution of the corresponding differential equation : 1. y = e^(x) + 1 : y'' - y' = 0

In each of the Exercises 1 to 10 vrify that the given functions(explicit or implicit) is a solution of the corresponding differential equation : 1. y = e^(x) + 1 : y'' - y' = 0

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y = e^x + 1 : y'' - y' = 0

Verify that the given function (explicit or implicit) isa solution of the correseponding differential equation : y = e^x + 1 : y'' - y' = 0

In each of the Exercises 1 to 10 vrify that the given functions(explicit or implicit) is a solution of the corresponding differential equation : 1. y = e^(x) + 1 : y" - y' = 0

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: (1)y = e^x +1: y"-y=0(2) y=x^2+2x+C : yprime-2x-2=0 (3) y=cos x+c : y'+sinx=0

The solution of the differential equation dy/dx=e^(y-x)+e^(y+x) ; y(0) = 0 is (1) y=e^x(x+1) (2) e^-y=(e^-x-e^x)+1 (3) e^-y =(e^-x-e^x)-1 (4) e^-y =(e^-x+e^x)+1