`((cosalpha-cos3alpha)(sin8alpha+sin2alpha))/((sin5alpha-sinalpha)(cos4alpha-cos6alpha))=`

((cos alpha-cos3 alpha)(sin8 alpha+sin2 alpha))/((sin5 alpha-sin alpha)(cos4 alpha-cos6 alpha))=

(( cos alpha - cos 3 alpha ) ( sin 8 alpha + sin 2 alpha ))/( ( sin 5 alpha - sin alpha ) ( cos 4 alpha - cos 6 alpha ))=

Prove the following : (cos7alpha+cos3alpha-cos5alpha-cosalpha)/(sin7alpha-sin3alpha-sin5alpha+sinalpha) = cot2alpha

(sin alpha*sin3 alpha+sin3 alpha*sin7 alpha+sin5 alpha*sin15 alpha)/(sin alpha*cos3 alpha+sin3 alpha cos7 alpha+sin5 alpha*cos15 alpha)=

Prove that, (cos alpha + sin alpha)/(cos alpha -sin alpha)-(cos alpha - sin alpha)/(cos alpha + sin alpha) = 2 tan 2 alpha

|(sin alpha, cos alpha),(cos alpha, -sin alpha)|=

Prove that (sin alpha+sin2 alpha+sin3alpha+sin4alpha)/(cos alpha+cos 2 alpha+cos 3 alpha+cos4 alpha)=tan((5 alpha)/2)

(sin 5 alpha-sin3alpha)/(cos 5 alpha+2 cos 4 alpha+cos 3alpha)=

The value of (sin5alpha-sin3alpha)/(cos5alpha+2cos4alpha+cos3alpha) is