Solve that following equations: `tantheta+tan2theta+"tan"3theta"="tanthetatan2thetatan3theta`

Explanation

Given equation is:


`tantheta+tan2theta+"tan"3theta"="tanthetatan2thetatan3theta`


`=>(sin theta/ cos theta)+(sin (2theta)/ cos (2theta))+(sin (3theta)/ cos (3theta)) = (sin theta/ cos theta) (sin (2theta)/ cos( 2theta))(sin (3theta)/ cos (3theta))`


`=>(sin theta cos 2theta cos 3theta +costhetacos3theta sin 2theta +costheta cos2 theta sin 3theta)/(costheta cos2theta cos3theta) = (sin theta sin2theta sin3theta)/(costheta cos2theta cos3theta) `


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