Solve that following equations : `"tantheta"+"tan"2"theta"+sqrt(3)"tanthetatan"2"theta"=""sqrt(3)`

Explanation

`sintheta/costheta+(cos2theta)/cos2theta+sqrt3sintheta/costheta*(sin2theta)/cos2theta=sqrt3`

`(sinthetacos2theta+sin2thetacostheta+sqrt3sinthetasin2theta)/(costhetacos2theta)=sqrt3`

`sin(theta+2theta)+sqrt3(sinthetasin2theta-costhetacos2theta)=0`

`sin3theta-sqrt3(costhetacostheta-sinthetasin2theta)=0`

`sin3theta-sqrt3cos3theta=0`

`tan3theta=sqrt3`

`theta=pi/9`

General solution

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