If in a `triangleABC` , `a = 6, b=3` and `cos(A-B)=4/5` then find its area.

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.

If in a triangle ABC , a = 6 , b = 3 and cos (A -B) = 4/5 ,then its area in square units, is

In DeltaABC , If in a DeltaABC , a = 6, b = 3 and cos(A-B)=4/5 , find its area.

If in a /_ABC,a=6,b=3 and cos(A-B)=(4)/(5) then find its area.

If in a triangle ABC,a=6,b=3 and cos(A-B)=(4)/(5) find the area of the triangle.

In DeltaABC, a=6,b=4 and cos (A-B)=4//5 then its area is

If in a !ABC , a = 6 , b = 3 and cos (A -B) = 4/5 ,then its area in square units, is

In Delta ABC , if : a = 6, b = 3, cos (A - B) = 4//5 , then : its area =

In a triangle ABC, two sides are a = 6, b = 3 and cos(A-B) =(4)/(5) then the area of the triangle is