Solve: `4sinxsin2xsin4x=sin3x`

Explanation

`4sinxsin2xsin4x = sin3x`

`=>4sinxsin(3x-x)sin(3x+x) = sin3x`

We know, `sin(A-B)sin(A+B) = sin^2A-sin^2B`

So, our equation becomes,

`=>4sinx(sin^2 3x - sin^2 x) = 3sinx-4sin^3x`

`=>4sinxsin^2 3x - 4sin^3x = 3sinx - 4sin^3 x`

`=>4sinxsin^2 3x -3sinx = 0`

`=>sinx(4sin^2 3x - 3) = 0`

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