If `sin^(-1)(a-a^2/3+a^3/9-...)+cos^(-1)(1+b+b^2+...)=pi/2` then find `a` and `b`

sin^(-1)(a-a^2/3+a^3/9+....)+cos^(-1)(1+b+b^2+....)=pi/2 when a) a = -3 and b = 1 b) a = 1 and b =1 c) a = 1/6 and b =1 d)None of these

(a) sin^(-1)(-1/2)=? (b) cos^(-1)(sqrt3/2)=?

sin ^ (- 1) (a- (a ^ (2)) / (3) + (a ^ (3)) / (9) + (a ^ (3)) / (9) +) + cos ^ ( -1) (1 + b + b ^ (2) +) = (pi) / (2) sin a - + ... + cos11 + b + b2 + ...

If sin(A-B)=1/2 and cos(A+B)=1/2 , find A and B.

Number of ordered pairs (a,b) for which sin^(-1)(1+b+b^2+..oo)+cos^(-1)(a-a^2/3+a^4/9+..oo)=pi/2 is (A) 0 (B) 4 (C) 9 (D) Infinite

Let f(x)={(1-sin^3x)/(3cos^2x) if x pi/2 find a and b. .

If a=sin^(-1)(-(sqrt(2))/(2))+cos^(-1)(-(1)/(2)) and b=tan^(-1)(-sqrt(3))-cot^(-1)(-(1)/(sqrt(3))) ,then find a-b " and " a+b

If sin(A+B)=1 and cos(A-B)=(sqrt(3))/(2) then find A and B

If sin A = (1)/(2) , cos B = 1, 0 lt A, B le (pi)/(2) then find the value of (A + B).

If sin (A-B)= 1/2 , cos(A+B)= 1/2 . Find A and B.