Solve that following equations : `cos e ctheta=1+cottheta`

Explanation

Given:
`1+cottheta=cosectheta`
`1+(costheta/sintheta)=1/sintheta`
`(sintheta+costheta)/sintheta=1/sintheta`
`sintheta+costheta=1`
Squaring both sides
`implies (sintheta+costheta)^2=1`
`implies sin^2theta+cos^2theta+2sinthetacostheta=1`
`implies 1+2sinthetacostheta=1`
`implies sin2theta=0`
`theta=2npi+pi/2`