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Solve that following equations : cotthe...

Solve that following equations : `cottheta+t a ntheta=2`

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Given:
`cottheta+tantheta=2`
`costheta/sintheta+sintheta/costheta=2`
Taking LCM
`(cos^2theta+sin^2theta)/(sinthetacostheta)=2`
Using Identity
`sin^2theta+cos^2theta=1`
`1/(sinthetacostheta)=2`
`1=2sinthetacostheta`
`1=sin2theta`
`sin2theta=sin(pi/2)`
Hence the general solution is
`2theta=npi+(-1)^npi/2`where,`n in Z`
`theta=(npi)/2+(-1)^npi/4`
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