Write the values of `x in[0,pi]` for which `sin2x ,1/2a n dcos2x` are in `AdotPdot`

Explanation

`sin2x,1/2x,cos2x `are in A.P.
`sin2x+cos2x=2times1/2`
`sin2x+cos2x=1`
This equation is of the form `asintheta+bcostheta=c`where,`a=1,b=1 and c=1`
Let `a=rsinalpha` and `b=rcosalpha`
`r=sqrt(a^2+b^2)=sqrt(1^2+1^2)=sqrt2`
`tanalpha=1 implies alpha =pi/4`