Find the general solutions of the following equations: (i) `cos3theta=0` (ii) `cos((3theta)/2)=0` (iii) `cos^2 3theta=0`

Explanation

We know that the general form of the equation `cos theta=0` is `theta=(2n+1)pi/2`,`ninZZ `

`cos3theta=0 =>``3theta = (2n+1)pi/2,n in ZZ`
dividing both sides by 3
` =>theta =(2n+1)pi/6 ,n inZZ`
(ii)`cos3 theta//2=0``=>``3theta//2 = (2n+1)pi/2`,`n in ZZ`
multiplying both sides by `2/3`
`=> theta =(2n+1)pi/3`,`n in ZZ`
(iii)`cos^2 3theta=0=>cos3theta=0`
`=>3theta=(2n+1)pi/2,n in ZZ`
dividing both side by 3
`=>theta =(2n+1)pi/6`,`n inZZ`