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CH(3)-overset(O)overset(||)(C)-CH(2)-CH(...

`CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-overset(O)overset(||)(C)-CH_(3) overset((NH_(4))_(2)CO_(3))underset(Delta) to (A) overset(C Cl_(3) CO_(2)Na) underset(Delta) to underset(("major"))((B))`
Product (B) of above reaction is :

A

B

C

D

Text Solution

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The correct Answer is:
To solve the given problem step by step, we will first analyze the reaction and then determine the product (B) formed. ### Step 1: Identify the Starting Compound The starting compound is: \[ \text{CH}_3 - \text{C}(=O) - \text{CH}_2 - \text{CH}_2 - \text{C}(=O) - \text{CH}_3 \] This is a symmetrical compound with two carbonyl (C=O) groups. ### Step 2: Reaction with Ammonium Carbonate When the compound is heated with ammonium carbonate \((\text{NH}_4)_2\text{CO}_3\), a condensation reaction occurs. This leads to the formation of a cyclic compound, specifically a substituted pyridine ring. The reaction involves the formation of a nitrogen-containing heterocycle. ### Step 3: Formation of Product A The product A formed from this reaction is a substituted pyridine ring, which can be represented as: \[ \text{C}_5\text{H}_6\text{N} \] with two methyl groups attached to the nitrogen-containing ring. ### Step 4: Reaction with Trichloroacetic Acid Sodium Salt Next, the product A is treated with trichloroacetic acid sodium salt \((\text{CCl}_3\text{CO}_2\text{Na})\). This reagent acts as a chlorinating agent. ### Step 5: Chlorination of the Pyridine Ring In this step, we need to consider the directing effects of the substituents on the pyridine ring. The nitrogen atom in the pyridine ring is a meta-directing group for electrophilic substitution reactions. Therefore, when chlorine is introduced to the ring, it will preferentially substitute at the meta position relative to the nitrogen. ### Step 6: Identify Product B The major product (B) will thus have a chlorine atom substituted at the meta position of the pyridine ring. The structure of product B can be represented as: \[ \text{C}_5\text{H}_5\text{Cl}\text{N} \] with the chlorine atom at the meta position relative to the nitrogen. ### Final Answer The product (B) of the reaction is a chlorinated substituted pyridine, where chlorine is at the meta position. ---

To solve the given problem step by step, we will first analyze the reaction and then determine the product (B) formed. ### Step 1: Identify the Starting Compound The starting compound is: \[ \text{CH}_3 - \text{C}(=O) - \text{CH}_2 - \text{CH}_2 - \text{C}(=O) - \text{CH}_3 \] This is a symmetrical compound with two carbonyl (C=O) groups. ### Step 2: Reaction with Ammonium Carbonate ...
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