Which of the following will form stable hydrate ?

Options

A. `CCl_(3)CHO` (Chloral)
B.
C. `(CF_(3))_(2) CO`
D. all of these

Explanation

To determine which of the given compounds will form stable hydrates, we need to analyze the structure of each compound and the presence of electron-withdrawing groups that can stabilize the hydrate formation. Here’s a step-by-step solution:

### Step 1: Understand Hydrate Formation
Hydrates are formed when water molecules attack the carbonyl carbon (C=O) of aldehydes and ketones. The stability of the hydrate depends on the presence of electron-withdrawing groups that can stabilize the positive charge developed during the formation of the hydrate.

### Step 2: Analyze Compound A (CCl3CHO)
- **Structure**: CCl3CHO (Chloral)
- **Electron-Withdrawing Groups**: The three chlorine atoms (CCl3) are strong electron-withdrawing groups.
- **Stability of Hydrate**: The presence of three chlorine atoms increases the electrophilicity of the carbonyl carbon, making it more susceptible to attack by water. Therefore, a stable hydrate will be formed.

### Step 3: Analyze Compound B (Benzaldehyde Derivative)
- **Structure**: A benzene ring with a carbonyl group (C=O).
- **Electron-Withdrawing Groups**: If there are substituents on the benzene ring that are electron-withdrawing, they will enhance the stability of the hydrate.
- **Stability of Hydrate**: Assuming there are electron-withdrawing groups on the benzene ring, the carbonyl carbon will be more electrophilic, allowing for stable hydrate formation.

### Step 4: Analyze Compound C (CF3)2CO
- **Structure**: A carbonyl group (C=O) with two trifluoromethyl (CF3) groups.
- **Electron-Withdrawing Groups**: The CF3 groups are very strong electron-withdrawing groups due to the high electronegativity of fluorine.
- **Stability of Hydrate**: The strong -I effect of the CF3 groups will significantly increase the electrophilicity of the carbonyl carbon, leading to the formation of a stable hydrate.

### Conclusion
Based on the analysis:
- **Compound A (CCl3CHO)** forms a stable hydrate.
- **Compound B** (assuming it has electron-withdrawing groups) can also form a stable hydrate.
- **Compound C ((CF3)2CO)** forms a stable hydrate.

Thus, all three compounds can potentially form stable hydrates depending on the presence of electron-withdrawing groups.

### Final Answer
All given compounds (A, B, and C) will form stable hydrates.