Home
Class 12
CHEMISTRY
elation between K(1) and K(2) is :...


elation between `K_(1)` and `K_(2)` is :

A

`K_(1) = K_(2)`

B

`K_(1) gt K_(2)`

C

`K_(2) gt K_(1)`

D

`K_(1) = K_(2) = 1`

Text Solution

Verified by Experts

The correct Answer is:
B

(b) More steric reactant easily convert into product .
Promotional Banner

Topper's Solved these Questions

  • ALDEHYDES AND KETONES

    MS CHOUHAN|Exercise Level 1 (Q.121 To Q.150)|1 Videos
  • ALDEHYDES AND KETONES

    MS CHOUHAN|Exercise Level 2|7 Videos
  • ALCOHOLS FROM CARBONYL COMPOUNDS

    MS CHOUHAN|Exercise Additional Objective Questions (Multiple Correct Choice Type )|1 Videos
  • ALDEHYDES AND KETONES I. NUCLEOPHILIC ADDITION TO THE CARBONYL GROUP

    MS CHOUHAN|Exercise ADDITIONAL OBJECTIVE QUESTIONS (SINGLE CORRECT CHOICE TYPE)|17 Videos

Similar Questions

Explore conceptually related problems

Consider the following equilibrium: SO_(2)(g)+(1)/(2)O_(2)(g)overset(K_(1))(hArr)SO_(3)(g), 2SO_(3)(g)overset(K_(2))(hArr) What is the relation between K_(1) and K_(2) ?

Elevation in the boiling point for 1 molal solution of glucose is 2K. The depression in the freezing point for 2 molal solution of glucose in the same solvent is 2K. The relation between K_(b) and K_(f) is

The equilibrium constant of the reactions SO_(2)(g)+1/2 O_(2)(g)hArrSO_(3)(g) and 2SO_(2)(g)+O_(2)hArr2SO_(3)(g) are K_(1) and K_(2) respectively. The relationship between K_(1) and K_(2) is

The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit of K_(p)=(atm)^(Deltan) , unit of K_(c)=(mol L^(-1))^(Deltan) Given: 2NO(g)+O_(2)(g) hArr 2NO_(2)(g), K_(1) 2NO_(2)(g) hArr N_(2)O_(4)(g), K_(2) 2NO(g)+O_(2)(g) hArr N_(2)O_(4)(g), K_(3) Which of the following relations is correct?

For the reaction 2AtoB+3C , if -(d[A])/(dt)=k_(1)[A]^(2),-(d[B])/(dt)=k_(2)[A]^(2),-(d[C])/(dt)=k_(3)[A]^(2) the correct reaction between k_(1),k_(2) and k_(3) is :

3BrO^(-) to BrO_(3)^(-) + 3Br^(-) If -(d[BrO^(-)])/(dt) = k_(1) [BrO^(-)]^(2), +(d[BrO_(3)^(-)])/(dt) =k_(2)[BrO^(-)]^(2) + (d[Br^(-)])/(dt) =k_(3)[BrO^(-)]^(2) , the correct relation between k_(1),k_(2) and k_(3) is

If K_(1) represents the equilibrium constant for reaction: H_(2)+I_(2)hArr2HI & K_(2)" for "(1)/(2)H_(2)+(1)/(2)I_(2)hArr HI the relation between K_(1)& K_(2) would be

For the reaction, N_(2)O_(5) rarr 2NO_(2)+1/2O_(2), Given -(d[N_(2)O_(5)])/(dt)=K_(1)[NO_(2)O_(5)] (d[NO_(2)])/(dt)=K_(2)[N_(2)O_(5)] and (d[O_(2)])/(dt)=K_(3)[N_(2)O_(5)] The relation in between K_(1), K_(2) and K_(3) is:

Consider the following reaction, 2N_(2)O_(5)rarr4NO_(2)+O_(2),(d[NO_(2)] )/(dt)=k_(2)[N_(2)O_(5)] , (d[O_(2)])/(dt)=k_(3)[N_(2)O_(5)]" and "(d)/(dt)[N_(2)O_(5)]=k_(1) The relation between k_(1), k_(2) and k_(3) is

For the reaction, I_(2)(aq)hArrI_(2)" (oil), Equilibrium constant is K"_(1). I_(2)"(oil)"hArrI_(2)"(ether), Equilibrium constant is K"_(2). I_(2)(aq)hArrI_(2)"(ether), Equilibrium constant is K"_(3). The reaction between K_(1), K_(2), K_(3) is