If 5 sinalpha=3"sin"(alpha+2beta)!=0, t...

If `5 sinalpha=3"sin"(alpha+2beta)!=0,` then `tan(alpha+beta)` is equal to

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To solve the problem, we need to find the value of \( \tan(\alpha + \beta) \) given the equation \( 5 \sin \alpha = 3 \sin(\alpha + 2\beta) \). ### Step-by-Step Solution: 1. **Start with the given equation**: \[ 5 \sin \alpha = 3 \sin(\alpha + 2\beta) \] ...

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Knowledge Check

If 3 sin beta=sin(2alpha+beta) , then tan (alpha+beta)-2 tan alpha is

A

independent of `alpha`

B

independent of `beta`

C

dependent of both `alpha` and `beta`.

D

independent of both `alpha` and `beta`.

If 3 sin beta = sin(2alpha +beta) , then tan (alpha+beta)-2 tan alpha is

A

independent of `alpha`

B

independent of `beta`

C

independent of both `alpha and beta`

D

independent of none of them

If sin alpha=A sin(alpha+beta),Ane0 , then The value of tan beta is

A

`(sinalpha(1+A cos beta))/(A cos alpha cos beta)`

B

`(sinalpha(1-A cos beta))/(A cos alpha cos beta)`

C

`(cos (1-A sinbeta))/(A cos alpha cos beta)`

D

`(cos alpha(1+A sin beta))/(A cos alpha cos beta)`

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