Text Solution
AI Generated Solution
|
Topper's Solved these Questions
TRIGONOMETRIC RATIOS OF COMPOUND ANGLES
RD SHARMA|Exercise Solved Examples And Exercises|149 VideosView Playlist
Similar Questions
Explore conceptually related problems
RD SHARMA-TRIGONOMETRIC RATIOS OF MULTIPLE AND SUBMULTIPLE ANGLES-Solved Examples And Exercises
- If t a n^2theta=2tan^2phi+1 , prove that cos2theta+sin^2phi=0.
05:20
|
Play - If theta=pi/(2^n+1) , prove that: 2^ncosthetacos2thetacos2^2 cos2^(n-1...
03:28
|
Play - Prove that: cotA+"cot"(60^0+A)-cot(60^0-A)=3cot3A
07:19
|
Playing Now - Prove that: cos^2 48^0-sin^2 12^0=(sqrt(5)+1)/8
02:11
|
Play - Find sin x/2 ,cos x/2 and tan x/2 of the following : tanx=-4/3,""x in...
03:51
|
Play - Find the values of cospi/8
01:02
|
Play - Prove that: sin(pi/14)sin((3pi)/14)sin((5pi)/14)sin((7pi)/14)sin((9pi...
04:03
|
Play - Prove that: (1+sec2theta)(1+sec4theta)(1+sec8theta)(1+sec2^ntheta)=t a...
04:58
|
Play - If theta=pi/(2^n+1) , prove that: 2^ncosthetacos2thetacos2^2 cos2^(n-1...
06:31
|
Play - Prove that: cos(pi/7)cos((2pi)/7)cos((4pi)/7)=-1/8,
04:28
|
Play - If alpha and beta are distict roots of acostheta+b sintheta=c , prov...
04:58
|
Play - sin^2(A/2+pi/8) - sin^2(A/2-pi/8)= 1/sqrt(2)sinA
04:13
|
Play - Sin 4A = 4 cos^3 A sin A - 4 sin^3 A cos A
02:07
|
Play - If tanA=1/7a n dtanB=1/3 , show that cos2A=sin4Bdot
03:37
|
Play - If 2t a nalpha/2=tan(beta/2) , prove that cosalpha=(3+5cosbeta)/(5+3c...
05:26
|
Play - If acos2theta+bsin2theta=ch a salphaa n dbeta as its roots , then prov...
02:51
|
Play - If cosalpha+cosbeta=0=sinalpha+sinbeta, then prove that cos2alpha+cos2...
02:38
|
Play - Prove that: sin((pi)/5)sin((2pi)/5)sin((3pi)/5)sin((4pi)/5)=5/(16)
05:11
|
Play - sin5theta =
02:45
|
Play - Prove that: sin^4(pi/8)+sin^4((3pi)/8)+sin^4((5pi)/8)+sin^4((7pi)/8)=...
04:26
|
Play