It is known that `sinbeta=4/5` and `0 < beta < pi` then the value of `(sqrt3 sin(alpha+beta)-2/cos(pi/6) cos(alpha+beta))/(sin alpha)` is

Solve the equation 6x^4-5x^3-38x^2-5x+6=0 if it is known that 1/3 is a solution.

If sinalpha=1/sqrt5 and sinbeta=3/5 , then beta-alpha lies in

If sinalpha=1/sqrt5 and sinbeta=3/5 , then beta-alpha lies in

If sinalpha=1/sqrt5 and sinbeta=3/5 , then beta-alpha lies in

Solve the equation 6x^(4)-5x^(3)-38x^(2)-5x+6=0 if it is known that (1)/(3) is a solution.

If sin alpha=sinbeta and cos alpha=cosbeta, then

If cosalpha+cosbeta=2/3 and sinalpha+sinbeta=2/5 then find the vvalue of tan((alpha+beta)/2)

If alpha,beta in (-pi/2,0) such that (sin alpha+sinbeta)+(sinalpha)/(sinbeta)=0 and (sinalpha+sinbeta) (sinalpha)/(sinbeta)=-1 and lambda=lim_(n->oo) (1+(2sinalpha)^(2n))/((2sinbeta)^(2n)) then :

CaS 0_4 is also known as