Home
Class 11
CHEMISTRY
Hydrogen can have "" oxidation number ( ...

Hydrogen can have `"____________"` oxidation number ( s) .

A

only -1

B

only +1

C

only 0

D

`-1,0,+1`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    TARGET PUBLICATION|Exercise CRITICAL THINGKIN|29 Videos

  • REDOX REACTIONS

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|21 Videos

  • NATURE OF CHEMICAL BOND

    TARGET PUBLICATION|Exercise Evaluation test|20 Videos

  • S-BLOCK ELEMENTS

    TARGET PUBLICATION|Exercise QUESTION|156 Videos

Similar Questions

Explore conceptually related problems

Oxidation number of Cl can be-

Assertion :- Oxidation state of Hydrogen is +1 in H_(2)O while -1 in CaH_(2) . Reason :- CaH_(2) is a metal hydride and for metal hydrides, hydrogen is assigned the oxidation number of -1 .

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Which of the following compounds have zero oxidation state at carbon

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Which of the following oxides of carbon has fractional oxidation state?

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Oxidation state of carbon in diamond is:

Oxidation number of S in KCNS is

Fluorine can have an oxidation number of .