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If tanalpha=(1-cosbeta)/(sinbeta),t h e ...

If `tanalpha=(1-cosbeta)/(sinbeta),t h e n` a)`tan3alpha=tan2beta` (b) `tan2alpha=tanbeta` (c) `tan2beta=tanalpha` (d) none of these

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Given,
`tan alpha=(1−cos beta)/(sin beta)`
using formula,
`1-cosbeta=2 sin^2 (beta/2)`
and
`sinbeta=2 sin( beta/2) cos (beta/2)`
`tanalpha=(2 sin^2 (beta/2))/((2 sin( beta/2) cos (beta/2)))=(sin(beta/2))/(cos(beta/2))`
...
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