A mechanc unsrew a nut by applying a force of 140 N with a spanner of length 40 cm . What should be the length of the spanner if a force of 40 N is applied to unsrew the same nut ?

Explanation

Given
Force `F_1=140 N`
Length `L_1=40 cm = 40 xx 10^(-2)m`
Force , `F_2=40 N`
Length , `L_2=?`
To find: `F_1 xx L_1 =F_2 xx L_2`
Length of the spanner ,
`L_2=(F_1 xx L_1)/(F_2)`
Solution
`L_2=(140 xx cancel(4)0 xx 10^(-2))/(cancel(4)0)`
`=140 xx 10^(-2)m`
Length `L_2=1.4 m`