A pistol fired a bullet of mass 50 g triggered with a speed `250 ms^(-1)` penetrated into a wooden plank comes to rest at 1 ms. Find the impulse and average force offered by the planks .

Explanation

Given
Mass , m=`50 g= 50 xx 10^(-3)` kg
Find speed , v=0
Initial speed , u`=250 ms^(-1)`
Time, t=1 ms =`10^(-3) s`
To find : `J= F xx t=?` Average force , F=ma=?
Solution
`F=(m(v-u))/(t)=(50 xx 10^(-3)[0-250])/(1 xx 10^(-3)s)`
`F= 12500 =1.25 xx 10^(4) N`
`J=F xx t=1.25 xx 10^(4) xx 10^(-3)`
`J= 12.5 Ns `