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Light in air enters a diamond at 45^(@) ...

Light in air enters a diamond at `45^(@)` . What is the angle of refraction ? G.T `mu_("dia")=2.42`.

Text Solution

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`mu_(a) sin i- mu_("dia")sin r" "……(1)`
(Reactive index of air , `mu_(a)=1`)
(Angle of incidence , i=`45^(@)`)
in (1),
`(1) implies (sin 45^(@))=2.42 (sin r)`
`sin r ((sin 45^(@))/(2.42))`
`r= sin^(-1)""((1)/(sqrt(2)))/(2.42)`
`r=sin^(-1) [(1)/(sqrt(2)xx 2.42)]`
Angle of refraction , `r=16.977 =17^(@)`
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