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A metal rod 6.522 m long at 285K expands...

A metal rod 6.522 m long at 285K expands by 0.576 m at 363K. Find the coefficient of linear expansion of the metal.

Text Solution

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Initial temperature, `T_(1) = 285K`
Final temperature , `T_(2) = 363K`
Initial length , `L_(0) = 6.522m`
Change in length, `DeltaL = 0.576 m`
To find : Coefficinet of linear expansion, `alpha_(L) = ?`
`alpha_(L) = (DeltaL)/(L_(0)DeltaT)`
`= (0.576)/(6.522(363-285)) =(0.576)/(6.522xx78)`
`alpha_(L) = 0.00113 = 1.13xx10^(-3) K^(-1)`
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