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""88Ra^(226) experiences three alpha-dec...

`""_88Ra^(226)` experiences three `alpha`-decay . Find the number of neutrons in the daughter element.

Text Solution

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`alpha`-decay : `""_zX^(A) to ""_(z-2)Y^(A-4) + ""_2He^(4)`
`3alpha`-decay:
`""_zX^(A) to ""_(z-6)Y^(A-12) + 3(""_2He^(4))`
`therefore ""_88Ra^(226) to ""_82Pb^(214) +3""_2He^(4) (or)`
`""_88Ra^(226) to ""_82X^(214) +3""_2He^(4)`
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