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An electron has a mass of 9.1×10^-31 kg ...

An electron has a mass of `9.1×10^-31` `kg` . It revolves round the nucleus in a circular orbit of radius `0.529×10^-10` `metre` at a speed of `2.2 ×10^6` m/s. The magnitude of its linear momentum in this motion is

A

`1 × 10^-34` kg-m/s

B

`2.0 × 10^-24` kg-m/s

C

`4.0 × 10^-24` kg-m/s

D

`4.0 × 10^-31` kg-m/s

Text Solution

Verified by Experts

The correct Answer is:
B
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An electron of mass 9 xx 10^(-31) kg revolves around a nucleus in a circular orbit of radius 0.53 Å . What is the angular momentum of the electron? (Velocity of electron is, v=2.2 xx 10^(6) ms^(-1)).

An electron of mass 9xx 10^(-31)kg revolves around a nucleus in a circular orbit of radius 0.53 Å . What is the angular momentum of the electron? (Velocity of electron is, v=2.2 xx 10^(6) ms^(-1) )

Knowledge Check

  • An electron has a mass of 9.1×10^-31 kg . It revolves round the nucleus in a circular orbit of radius 0.867×10^-12 metre at a speed of 4.8 ×10^8 m/s. The magnitude of its linear momentum in this motion is

    A
    `4.368 × 10^-22` kg-m/s
    B
    `2.834 × 10^-34` kg-m/s
    C
    `4.368 × 10^-24` kg-m/s
    D
    `2.834 × 10^-32` kg-m/s

  • An electron is revolving in an orbit of radius 2Å with a speed of 4 xx 10^(5) m//s . The angular momentum of the electron is [M_(e) 9=xx10^(-31) kg] .

    A
    `2xx10^(-35) kg m^(2) s^(-1)`
    B
    `72xx10^(-36)kg m^(2) s^(-1)`
    C
    `7.2xx10^(-34)kg m^(2) s^(-1)`
    D
    `0.72xx10^(-37) kg m^(2) s^(-1)`

  • An electron of mass 9xx10^(-31) kg revolves in a circle of radius 0.53 Å around the nucleus of hydrogen atom with a velocity of 2.2xx10^(6) "ms"^(-1) . What is the angular momentum of the electron ?

    A
    `(h)/(2pi)`
    B
    `(3h)/(3pi)`
    C
    `(h)/(pi)`
    D
    `(h)/(3pi)`

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