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Home
Class 10
CHEMISTRY
Arrive at , systematically , the IUPAC n...

Arrive at , systematically , the IUPAC name of the compound : `CH_3-CH_2-CH_2-OH` .

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Text Solution

Verified by Experts

Step 1: The parent chain consists of 3 carbon atoms. The root word is 'Prop'.
Step 2: There are single bonds between the carbon atoms of the chain . So, the primary suffix is 'ane'.
Step 3: Since , the compound contains - OH group , it is an alcohol. The carbon chain is numbered from the end which is closer to -OH group . (Rule 3)
`overset(3)(C)H_3-overset(2)(C)H_2-overset(1)(C)H_2-OH`
Step 4 : The locant number of -OH group is 1 and thus the secondary suffix is '1-ol`.
The name of the compound is Prop + ane + (1-ol)=Propan-1-ol
Note :- Terminal 'e' of 'ane' is removed as per Rule 5 .
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(i) Arrive at, sytematically, the IUPAC name of the compound: CH_(3)-CH_(2)-CH_(2)-OH . (ii) In magnesium sulphide, the ratio by mass of Mg and S is 3:4. what is the ratio of the number of Mg and S atoms?

Arrive at , systematically , the IUPAC name of the compoud : CH_(3) - CH_(2) - CH_(2) - OH .

Knowledge Check

  • The IUPAC name of the compound : CH_(3)-CH=CH-C-=CH is:

    A
    Pent- 4- yn - 2- ene
    B
    Pent -3 - en - 1- yne
    C
    Pent 2- en - 4 - yne
    D
    Pent - 1- yn - 3 - ene
  • The IUPAC name of the compound CH_(3)-CH=CH-C=CH is ............ .

    A
    Pent - 4-yn-2-ene
    B
    Pent-3-en-l-yne
    C
    pent-2-en-4-yne
    D
    Pent-1-yn-3-ene
  • The IUPAC name of the compound CH_(3) –CH= CH – C ≡ CH is

    A
    Pent - 4 - yn-2-ene
    B
    Pent -3-en-l-yne
    C
    pent – 2– en – 4 – yne
    D
    Pent – 1 – yn –3 –ene
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    Give the IUPAC names of the compounds. CH_(2)= CH-CH=CH_(2)

    The common name of this compound CH_(2)=CH-CH_(2)-OH is

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