The far position of a myopic person is 90 cm in front off the eye. What is the nature and power of the lens requried to correct the problem?

(a) Find the final temperature of a copper rod. Whose area of cross section changes from 10m^(2) to 11m^(2) due to heating. The copper rod is initially kept at 90K. (Coefficient of superficial expansion is 0.0021/K). (b) The far position of a myopic person is 90 cm is front of the eye. what is the nature and power of the lens required to correct the problem?

a. The far point of a myopic person is 80cm in front of the eye. What is the power of the lens required to enable him to see very distant object clearly ? b. In what way does the corrective lens help the above person ? Does the lens magnify very distant objects? Explain carefully. c. The above person profers to remove his spectacles while reading a book Explain why.

a. The near point of a hypermetropic person is 75 cm from the eye. What is the power of the lens required to enable the person to read clearly a book held at 25 cm from the eye? b . In what way does the corrective lens help the above person? Does the lens magnify objects held near the eye ? c. The above person prefers to remove the spectacles with looking at the sky. Explain why .

If the focal length is 150 cm for a glass lens, what is the power of the lens?

An object is placed at 50 cm from a lens produces a virtual image at a distance of 10 cm in front of the lens . What is the focal length of the lens ? Is it converging or diverging ?

For a normal eye, the far point is at infinity and the near point of distanct vision is about 25 cm in front of the eye. The cornea of the eye provides a converging power of about 40 dioptres, and the least converging power of the eye-lens behind the cornea is about 20 dioptres. From this rough data estimate the range of accommodation (i.e., the range of converaging power of the eye-lens) of a normal eye.

For a normal eye, the far point is at infinity and the near point of distanct vision is about 25 cm in front of the eye. The cornea of the eye provides a converging power of about 40 dioptres, and the least converging power of the eye-lens behind the cornnea is about 20 dioptres. from this rough data estimate the range of accommodation (i.e., the range of converging power of the eye-lens ) of a normal eye.

An object kept 60 cm from a lens gives a virtual image 20 cm in front of the lens. What is the focal length of the lens? Is it a converging lens or diverging lens?

The near point and the far point of a child are at 10 cm and 100 cm. If the retina is 2.0 cm behind the eye-lens, what is the range of the power of the eye-lens?