Find the magnitude of two vectors `vec(a) and vec(b)` having the same magnitude and such that the angle between them is `60^@` and their scalar product is `1//2`.

Explanation

Both vectors have same magnitude i.e., `|a|=|b|` and scalar product of vectors, `vec(a).vec(b)=(1)/(2)`.
Let `theta` be the angle between two vectors a and b , then
`cos theta =(a.b)/(|a||b|)rArr cos 60^@ =((1)/(2))/(|a||a|)[because |a|=|b|]`
`rArr (1)/(2)=(1)/(2|a|^2)rArr |a|^2=1rArr |a|=1`.
Thus, `|a|=|b|=1`.